14242101131 has 2 divisors, whose sum is σ = 14242101132. Its totient is φ = 14242101130.

The previous prime is 14242101113. The next prime is 14242101151. The reversal of 14242101131 is 13110124241.

Together with previous prime (14242101113) it forms an Ormiston pair, because they use the same digits, order apart.

It is an a-pointer prime, because the next prime (14242101151) can be obtained adding 14242101131 to its sum of digits (20).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14242101131 is a prime.

It is a super-2 number, since 2×14242101131² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14242101151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7121050565 + 7121050566.

It is an arithmetic number, because the mean of its divisors is an integer number (7121050566).

Almost surely, 2^14242101131 is an apocalyptic number.

14242101131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14242101131 is an equidigital number, since it uses as much as digits as its factorization.

14242101131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 14242101131 its reverse (13110124241), we get a palindrome (27352225372).

The spelling of 14242101131 in words is "fourteen billion, two hundred forty-two million, one hundred one thousand, one hundred thirty-one".