1424222113 has 2 divisors, whose sum is σ = 1424222114. Its totient is φ = 1424222112.

The previous prime is 1424222099. The next prime is 1424222131. The reversal of 1424222113 is 3112224241.

Together with next prime (1424222131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1134813969 + 289408144 = 33687^2 + 17012^2 .

It is a cyclic number.

It is not a de Polignac number, because 1424222113 - 2²¹ = 1422124961 is a prime.

It is not a weakly prime, because it can be changed into another prime (1424222143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712111056 + 712111057.

It is an arithmetic number, because the mean of its divisors is an integer number (712111057).

Almost surely, 2^1424222113 is an apocalyptic number.

It is an amenable number.

1424222113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1424222113 is an equidigital number, since it uses as much as digits as its factorization.

1424222113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 768, while the sum is 22.

The square root of 1424222113 is about 37738.8674048387. The cubic root of 1424222113 is about 1125.1037568172.

Adding to 1424222113 its reverse (3112224241), we get a palindrome (4536446354).

The spelling of 1424222113 in words is "one billion, four hundred twenty-four million, two hundred twenty-two thousand, one hundred thirteen".