1424222131 has 2 divisors, whose sum is σ = 1424222132. Its totient is φ = 1424222130.

The previous prime is 1424222113. The next prime is 1424222143. The reversal of 1424222131 is 1312224241.

Together with previous prime (1424222113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (1312224241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1424222131 - 2⁵ = 1424222099 is a prime.

It is a super-2 number, since 2×1424222131² = 4056817356860362322, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1424222171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712111065 + 712111066.

It is an arithmetic number, because the mean of its divisors is an integer number (712111066).

Almost surely, 2^1424222131 is an apocalyptic number.

1424222131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1424222131 is an equidigital number, since it uses as much as digits as its factorization.

1424222131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 768, while the sum is 22.

The square root of 1424222131 is about 37738.8676433197. The cubic root of 1424222131 is about 1125.1037615571.

Adding to 1424222131 its reverse (1312224241), we get a palindrome (2736446372).

The spelling of 1424222131 in words is "one billion, four hundred twenty-four million, two hundred twenty-two thousand, one hundred thirty-one".