Base | Representation |
---|---|
bin | 10100101110011100001… |
… | …011010111011010000011 |
3 | 12001011020201220222112211 |
4 | 110232130023113122003 |
5 | 141313333111301011 |
6 | 3010143214402551 |
7 | 204620231436613 |
oct | 24563413273203 |
9 | 5034221828484 |
10 | 1424254400131 |
11 | 4aa02852a082 |
12 | 1b0043b00457 |
13 | a43ca826624 |
14 | 4cd11948a43 |
15 | 270ac653b21 |
hex | 14b9c2d7683 |
1424254400131 has 2 divisors, whose sum is σ = 1424254400132. Its totient is φ = 1424254400130.
The previous prime is 1424254400059. The next prime is 1424254400161. The reversal of 1424254400131 is 1310044524241.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1424254400131 - 213 = 1424254391939 is a prime.
It is a super-2 number, since 2×14242544001312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1424254400093 and 1424254400102.
It is not a weakly prime, because it can be changed into another prime (1424254400161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712127200065 + 712127200066.
It is an arithmetic number, because the mean of its divisors is an integer number (712127200066).
Almost surely, 21424254400131 is an apocalyptic number.
1424254400131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1424254400131 is an equidigital number, since it uses as much as digits as its factorization.
1424254400131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15360, while the sum is 31.
Adding to 1424254400131 its reverse (1310044524241), we get a palindrome (2734298924372).
The spelling of 1424254400131 in words is "one trillion, four hundred twenty-four billion, two hundred fifty-four million, four hundred thousand, one hundred thirty-one".
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