Base | Representation |
---|---|
bin | 1100111101000011011011… |
… | …1011000010101000101011 |
3 | 1212102121202110101120020221 |
4 | 3033100312323002220223 |
5 | 3331324212422003431 |
6 | 50143054203430511 |
7 | 3000011430644311 |
oct | 317206673025053 |
9 | 55377673346227 |
10 | 14243033000491 |
11 | 45a14888a4aa9 |
12 | 172048ab25437 |
13 | 7c415c7c2809 |
14 | 37351b8740b1 |
15 | 19a76226b111 |
hex | cf436ec2a2b |
14243033000491 has 2 divisors, whose sum is σ = 14243033000492. Its totient is φ = 14243033000490.
The previous prime is 14243033000411. The next prime is 14243033000501. The reversal of 14243033000491 is 19400033034241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14243033000491 is a prime.
It is not a weakly prime, because it can be changed into another prime (14243033000401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7121516500245 + 7121516500246.
It is an arithmetic number, because the mean of its divisors is an integer number (7121516500246).
Almost surely, 214243033000491 is an apocalyptic number.
14243033000491 is a deficient number, since it is larger than the sum of its proper divisors (1).
14243033000491 is an equidigital number, since it uses as much as digits as its factorization.
14243033000491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 34.
The spelling of 14243033000491 in words is "fourteen trillion, two hundred forty-three billion, thirty-three million, four hundred ninety-one", and thus it is an aban number.
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