Base | Representation |
---|---|
bin | 100000011000101010010110… |
… | …101011010101101000000000 |
3 | 200200022101111020111210202122 |
4 | 200120222112223111220000 |
5 | 122132102203223204440 |
6 | 1222532244214103412 |
7 | 42000250344135410 |
oct | 4030522653255000 |
9 | 620271436453678 |
10 | 142432233413120 |
11 | 41424197619822 |
12 | 13b843a294ab68 |
13 | 61623c05a8201 |
14 | 2725a84c42640 |
15 | 116eec8b087b5 |
hex | 818a96ad5a00 |
142432233413120 has 320 divisors, whose sum is σ = 414577022086656. Its totient is φ = 45813509652480.
The previous prime is 142432233413059. The next prime is 142432233413131. The reversal of 142432233413120 is 21314332234241.
It is a happy number.
142432233413120 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (320).
It is a super-2 number, since 2×1424322334131202 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 93991364 + ... + 95494716.
Almost surely, 2142432233413120 is an apocalyptic number.
142432233413120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 142432233413120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (207288511043328).
142432233413120 is an abundant number, since it is smaller than the sum of its proper divisors (272144788673536).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
142432233413120 is a wasteful number, since it uses less digits than its factorization.
142432233413120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1503711 (or 1503695 counting only the distinct ones).
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 142432233413120 its reverse (21314332234241), we get a palindrome (163746565647361).
The spelling of 142432233413120 in words is "one hundred forty-two trillion, four hundred thirty-two billion, two hundred thirty-three million, four hundred thirteen thousand, one hundred twenty".
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