14243313102032 has 80 divisors (see below), whose sum is σ = 31695251612160. Its totient is φ = 6074020859904.

The previous prime is 14243313102001. The next prime is 14243313102037. The reversal of 14243313102032 is 23020131334241.

14243313102032 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 14243313101986 and 14243313102004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14243313102037) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43361033 + ... + 43688279.

It is an arithmetic number, because the mean of its divisors is an integer number (396190645152).

Almost surely, 2^{14243313102032} is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14243313102032, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15847625806080).

14243313102032 is an abundant number, since it is smaller than the sum of its proper divisors (17451938510128).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14243313102032 is a wasteful number, since it uses less digits than its factorization.

14243313102032 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 329188 (or 329182 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 14243313102032 its reverse (23020131334241), we get a palindrome (37263444436273).

The spelling of 14243313102032 in words is "fourteen trillion, two hundred forty-three billion, three hundred thirteen million, one hundred two thousand, thirty-two".