Base | Representation |
---|---|
bin | 1100111101000100110110… |
… | …0010011101010001110011 |
3 | 1212102122201220100200102022 |
4 | 3033101031202131101303 |
5 | 3331331002040310422 |
6 | 50143200000142055 |
7 | 3000024016031504 |
oct | 317211542352163 |
9 | 55378656320368 |
10 | 14243412431987 |
11 | 45a1662aa1552 |
12 | 172057600792b |
13 | 7c41c02b1cab |
14 | 373556002bab |
15 | 19a78571a342 |
hex | cf44d89d473 |
14243412431987 has 2 divisors, whose sum is σ = 14243412431988. Its totient is φ = 14243412431986.
The previous prime is 14243412431981. The next prime is 14243412432013. The reversal of 14243412431987 is 78913421434241.
It is a weak prime.
It is an emirp because it is prime and its reverse (78913421434241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14243412431987 - 210 = 14243412430963 is a prime.
It is not a weakly prime, because it can be changed into another prime (14243412431981) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7121706215993 + 7121706215994.
It is an arithmetic number, because the mean of its divisors is an integer number (7121706215994).
Almost surely, 214243412431987 is an apocalyptic number.
14243412431987 is a deficient number, since it is larger than the sum of its proper divisors (1).
14243412431987 is an equidigital number, since it uses as much as digits as its factorization.
14243412431987 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4644864, while the sum is 53.
The spelling of 14243412431987 in words is "fourteen trillion, two hundred forty-three billion, four hundred twelve million, four hundred thirty-one thousand, nine hundred eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •