Base | Representation |
---|---|
bin | 11010100010000001… |
… | …11011100011001111 |
3 | 1100202200210021020111 |
4 | 31101000323203033 |
5 | 213132442202203 |
6 | 10313232300451 |
7 | 1012660566136 |
oct | 152100734317 |
9 | 40680707214 |
10 | 14244100303 |
11 | 604a472424 |
12 | 29163a1727 |
13 | 1460067124 |
14 | 991a9891d |
15 | 58579e26d |
hex | 35103b8cf |
14244100303 has 2 divisors, whose sum is σ = 14244100304. Its totient is φ = 14244100302.
The previous prime is 14244100279. The next prime is 14244100313. The reversal of 14244100303 is 30300144241.
14244100303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14244100303 - 213 = 14244092111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14244100313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7122050151 + 7122050152.
It is an arithmetic number, because the mean of its divisors is an integer number (7122050152).
Almost surely, 214244100303 is an apocalyptic number.
14244100303 is a deficient number, since it is larger than the sum of its proper divisors (1).
14244100303 is an equidigital number, since it uses as much as digits as its factorization.
14244100303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 14244100303 its reverse (30300144241), we get a palindrome (44544244544).
The spelling of 14244100303 in words is "fourteen billion, two hundred forty-four million, one hundred thousand, three hundred three".
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