Base | Representation |
---|---|
bin | 11010100010000010… |
… | …10111001001101001 |
3 | 1100202201000000022112 |
4 | 31101001113021221 |
5 | 213133004311403 |
6 | 10313234532105 |
7 | 1012661546546 |
oct | 152101271151 |
9 | 40681000275 |
10 | 14244213353 |
11 | 604a53a357 |
12 | 2916437035 |
13 | 14600a6716 |
14 | 991ac7bcd |
15 | 5857c29d8 |
hex | 351057269 |
14244213353 has 2 divisors, whose sum is σ = 14244213354. Its totient is φ = 14244213352.
The previous prime is 14244213331. The next prime is 14244213377. The reversal of 14244213353 is 35331244241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14243706409 + 506944 = 119347^2 + 712^2 .
It is a cyclic number.
It is not a de Polignac number, because 14244213353 - 28 = 14244213097 is a prime.
It is a super-2 number, since 2×142442133532 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14244213253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7122106676 + 7122106677.
It is an arithmetic number, because the mean of its divisors is an integer number (7122106677).
Almost surely, 214244213353 is an apocalyptic number.
It is an amenable number.
14244213353 is a deficient number, since it is larger than the sum of its proper divisors (1).
14244213353 is an equidigital number, since it uses as much as digits as its factorization.
14244213353 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 34560, while the sum is 32.
Adding to 14244213353 its reverse (35331244241), we get a palindrome (49575457594).
The spelling of 14244213353 in words is "fourteen billion, two hundred forty-four million, two hundred thirteen thousand, three hundred fifty-three".
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