Base | Representation |
---|---|
bin | 1000010010101010110… |
… | …0100111011011100001 |
3 | 111121200121021222010202 |
4 | 2010222230213123201 |
5 | 4313214231302211 |
6 | 145235111234545 |
7 | 13202023141352 |
oct | 2045254473341 |
9 | 447617258122 |
10 | 142450259681 |
11 | 5545a504544 |
12 | 23736378a55 |
13 | 105823c72b2 |
14 | 6c74c11d29 |
15 | 3a8adc453b |
hex | 212ab276e1 |
142450259681 has 2 divisors, whose sum is σ = 142450259682. Its totient is φ = 142450259680.
The previous prime is 142450259659. The next prime is 142450259713. The reversal of 142450259681 is 186952054241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 102394240081 + 40056019600 = 319991^2 + 200140^2 .
It is a cyclic number.
It is not a de Polignac number, because 142450259681 - 218 = 142449997537 is a prime.
It is a super-2 number, since 2×1424502596812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (142450259621) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71225129840 + 71225129841.
It is an arithmetic number, because the mean of its divisors is an integer number (71225129841).
Almost surely, 2142450259681 is an apocalyptic number.
It is an amenable number.
142450259681 is a deficient number, since it is larger than the sum of its proper divisors (1).
142450259681 is an equidigital number, since it uses as much as digits as its factorization.
142450259681 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 691200, while the sum is 47.
The spelling of 142450259681 in words is "one hundred forty-two billion, four hundred fifty million, two hundred fifty-nine thousand, six hundred eighty-one".
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