Base | Representation |
---|---|
bin | 100000011000111100010000… |
… | …000110111101000000101011 |
3 | 200200101020002111222020210122 |
4 | 200120330100012331000223 |
5 | 122132411032321032101 |
6 | 1222545143140233455 |
7 | 42001530512212304 |
oct | 4030742006750053 |
9 | 620336074866718 |
10 | 142451450564651 |
11 | 41431359162138 |
12 | 13b8806669b88b |
13 | 6164163a269a7 |
14 | 27269891857ab |
15 | 1170750c8951b |
hex | 818f101bd02b |
142451450564651 has 2 divisors, whose sum is σ = 142451450564652. Its totient is φ = 142451450564650.
The previous prime is 142451450564617. The next prime is 142451450564671. The reversal of 142451450564651 is 156465054154241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142451450564651 - 222 = 142451446370347 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 142451450564593 and 142451450564602.
It is not a weakly prime, because it can be changed into another prime (142451450564671) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71225725282325 + 71225725282326.
It is an arithmetic number, because the mean of its divisors is an integer number (71225725282326).
Almost surely, 2142451450564651 is an apocalyptic number.
142451450564651 is a deficient number, since it is larger than the sum of its proper divisors (1).
142451450564651 is an equidigital number, since it uses as much as digits as its factorization.
142451450564651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520000, while the sum is 53.
The spelling of 142451450564651 in words is "one hundred forty-two trillion, four hundred fifty-one billion, four hundred fifty million, five hundred sixty-four thousand, six hundred fifty-one".
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