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1424525471303 = 111728127109549
BaseRepresentation
bin10100101110101100010…
…101011010111001000111
312001011221121222211021212
4110232230111122321013
5141314412010040203
63010230140402035
7204630032501564
oct24565425327107
95034847884255
101424525471303
114aa157544940
121b00ba84631b
13a4441a35b7c
144cd3994b86b
15270c634b1d8
hex14bac55ae47

1424525471303 has 16 divisors (see below), whose sum is σ = 1651296909600. Its totient is φ = 1214507750400.

The previous prime is 1424525471231. The next prime is 1424525471321. The reversal of 1424525471303 is 3031745254241.

It is a cyclic number.

It is not a de Polignac number, because 1424525471303 - 210 = 1424525470279 is a prime.

It is a super-4 number, since 4×14245254713034 (a number of 50 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1424525471203) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13502228 + ... + 13607321.

It is an arithmetic number, because the mean of its divisors is an integer number (103206056850).

Almost surely, 21424525471303 is an apocalyptic number.

1424525471303 is a deficient number, since it is larger than the sum of its proper divisors (226771438297).

1424525471303 is a wasteful number, since it uses less digits than its factorization.

1424525471303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27109858.

The product of its (nonzero) digits is 403200, while the sum is 41.

The spelling of 1424525471303 in words is "one trillion, four hundred twenty-four billion, five hundred twenty-five million, four hundred seventy-one thousand, three hundred three".

Divisors: 1 11 17 187 281 3091 4777 52547 27109549 298205039 460862333 5069485663 7617783269 83795615959 129502315573 1424525471303