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1424525471321 is a prime number
BaseRepresentation
bin10100101110101100010…
…101011010111001011001
312001011221121222211022112
4110232230111122321121
5141314412010040241
63010230140402105
7204630032501621
oct24565425327131
95034847884275
101424525471321
114aa157544957
121b00ba846335
13a4441a35b94
144cd3994b881
15270c634b1eb
hex14bac55ae59

1424525471321 has 2 divisors, whose sum is σ = 1424525471322. Its totient is φ = 1424525471320.

The previous prime is 1424525471231. The next prime is 1424525471423. The reversal of 1424525471321 is 1231745254241.

Together with previous prime (1424525471231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1006480465225 + 418045006096 = 1003235^2 + 646564^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1424525471321 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1424525471221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712262735660 + 712262735661.

It is an arithmetic number, because the mean of its divisors is an integer number (712262735661).

Almost surely, 21424525471321 is an apocalyptic number.

It is an amenable number.

1424525471321 is a deficient number, since it is larger than the sum of its proper divisors (1).

1424525471321 is an equidigital number, since it uses as much as digits as its factorization.

1424525471321 is an evil number, because the sum of its binary digits is even.

The product of its digits is 268800, while the sum is 41.

The spelling of 1424525471321 in words is "one trillion, four hundred twenty-four billion, five hundred twenty-five million, four hundred seventy-one thousand, three hundred twenty-one".