Base | Representation |
---|---|
bin | 10100101110101100010… |
… | …101011010110111111111 |
3 | 12001011221121222211012012 |
4 | 110232230111122313333 |
5 | 141314412010034411 |
6 | 3010230140401435 |
7 | 204630032501432 |
oct | 24565425326777 |
9 | 5034847884165 |
10 | 1424525471231 |
11 | 4aa157544885 |
12 | 1b00ba84627b |
13 | a4441a35b25 |
14 | 4cd3994b819 |
15 | 270c634b18b |
hex | 14bac55adff |
1424525471231 has 2 divisors, whose sum is σ = 1424525471232. Its totient is φ = 1424525471230.
The previous prime is 1424525471221. The next prime is 1424525471321. The reversal of 1424525471231 is 1321745254241.
Together with next prime (1424525471321) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1424525471231 - 218 = 1424525209087 is a prime.
It is a super-2 number, since 2×14245254712312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1424525471221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712262735615 + 712262735616.
It is an arithmetic number, because the mean of its divisors is an integer number (712262735616).
Almost surely, 21424525471231 is an apocalyptic number.
1424525471231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1424525471231 is an equidigital number, since it uses as much as digits as its factorization.
1424525471231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 268800, while the sum is 41.
The spelling of 1424525471231 in words is "one trillion, four hundred twenty-four billion, five hundred twenty-five million, four hundred seventy-one thousand, two hundred thirty-one".
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