Base | Representation |
---|---|
bin | 11010100010001011… |
… | …11000111001000011 |
3 | 1100202210020022021021 |
4 | 31101011320321003 |
5 | 213133310301011 |
6 | 10313320210311 |
7 | 1013004621544 |
oct | 152105707103 |
9 | 40683208237 |
10 | 14245400131 |
11 | 605017aa66 |
12 | 2916909997 |
13 | 1460400961 |
14 | 991d164cb |
15 | 585959471 |
hex | 351178e43 |
14245400131 has 2 divisors, whose sum is σ = 14245400132. Its totient is φ = 14245400130.
The previous prime is 14245400123. The next prime is 14245400153. The reversal of 14245400131 is 13100454241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14245400131 - 23 = 14245400123 is a prime.
It is a super-2 number, since 2×142454001312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14245400096 and 14245400105.
It is not a weakly prime, because it can be changed into another prime (14245400531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7122700065 + 7122700066.
It is an arithmetic number, because the mean of its divisors is an integer number (7122700066).
Almost surely, 214245400131 is an apocalyptic number.
14245400131 is a deficient number, since it is larger than the sum of its proper divisors (1).
14245400131 is an equidigital number, since it uses as much as digits as its factorization.
14245400131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1920, while the sum is 25.
Adding to 14245400131 its reverse (13100454241), we get a palindrome (27345854372).
The spelling of 14245400131 in words is "fourteen billion, two hundred forty-five million, four hundred thousand, one hundred thirty-one".
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