Base | Representation |
---|---|
bin | 11010100010101101… |
… | …00010011101111101 |
3 | 1100210002110001101012 |
4 | 31101112202131331 |
5 | 213140414432413 |
6 | 10313553525005 |
7 | 1013060000411 |
oct | 152126423575 |
9 | 40702401335 |
10 | 14249764733 |
11 | 6052691176 |
12 | 2918273765 |
13 | 146129b469 |
14 | 992730d41 |
15 | 58601c7a8 |
hex | 3515a277d |
14249764733 has 2 divisors, whose sum is σ = 14249764734. Its totient is φ = 14249764732.
The previous prime is 14249764703. The next prime is 14249764741. The reversal of 14249764733 is 33746794241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11172067204 + 3077697529 = 105698^2 + 55477^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14249764733 is a prime.
It is a super-2 number, since 2×142497647332 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14249764703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7124882366 + 7124882367.
It is an arithmetic number, because the mean of its divisors is an integer number (7124882367).
Almost surely, 214249764733 is an apocalyptic number.
It is an amenable number.
14249764733 is a deficient number, since it is larger than the sum of its proper divisors (1).
14249764733 is an equidigital number, since it uses as much as digits as its factorization.
14249764733 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3048192, while the sum is 50.
The spelling of 14249764733 in words is "fourteen billion, two hundred forty-nine million, seven hundred sixty-four thousand, seven hundred thirty-three".
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