14250240131 has 2 divisors, whose sum is σ = 14250240132. Its totient is φ = 14250240130.

The previous prime is 14250240079. The next prime is 14250240133. The reversal of 14250240131 is 13104205241.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14250240131 is a prime.

It is a super-2 number, since 2×14250240131² (a number of 21 digits) contains 22 as substring.

Together with 14250240133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14250240097 and 14250240106.

It is not a weakly prime, because it can be changed into another prime (14250240133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7125120065 + 7125120066.

It is an arithmetic number, because the mean of its divisors is an integer number (7125120066).

Almost surely, 2^14250240131 is an apocalyptic number.

14250240131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14250240131 is an equidigital number, since it uses as much as digits as its factorization.

14250240131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 14250240131 its reverse (13104205241), we get a palindrome (27354445372).

The spelling of 14250240131 in words is "fourteen billion, two hundred fifty million, two hundred forty thousand, one hundred thirty-one".