Search a number
-
+
14251387025153 is a prime number
BaseRepresentation
bin1100111101100010100011…
…0111000111011100000001
31212110102022122221222200202
43033120220313013130001
53331443320034301103
650150555151254545
73000425440663325
oct317305067073401
955412278858622
1014251387025153
1145a4a85496413
12172202081a455
137c4b9149a985
14373ab1175985
1519aaa0897988
hexcf628dc7701

14251387025153 has 2 divisors, whose sum is σ = 14251387025154. Its totient is φ = 14251387025152.

The previous prime is 14251387025147. The next prime is 14251387025179. The reversal of 14251387025153 is 35152078315241.

14251387025153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12883275491584 + 1368111533569 = 3589328^2 + 1169663^2 .

It is a cyclic number.

It is not a de Polignac number, because 14251387025153 - 210 = 14251387024129 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14251387025098 and 14251387025107.

It is not a weakly prime, because it can be changed into another prime (14251387025653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7125693512576 + 7125693512577.

It is an arithmetic number, because the mean of its divisors is an integer number (7125693512577).

Almost surely, 214251387025153 is an apocalyptic number.

It is an amenable number.

14251387025153 is a deficient number, since it is larger than the sum of its proper divisors (1).

14251387025153 is an equidigital number, since it uses as much as digits as its factorization.

14251387025153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008000, while the sum is 47.

The spelling of 14251387025153 in words is "fourteen trillion, two hundred fifty-one billion, three hundred eighty-seven million, twenty-five thousand, one hundred fifty-three".