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142521433 is a prime number
BaseRepresentation
bin10000111111010…
…11010001011001
3100221011211122121
420133223101121
5242441141213
622050421241
73350261245
oct1037532131
9327154577
10142521433
11734a450a
123b891821
13236b0c12
1414cdd425
15c7a388d
hex87eb459

142521433 has 2 divisors, whose sum is σ = 142521434. Its totient is φ = 142521432.

The previous prime is 142521419. The next prime is 142521461. The reversal of 142521433 is 334125241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121066009 + 21455424 = 11003^2 + 4632^2 .

It is a cyclic number.

It is not a de Polignac number, because 142521433 - 29 = 142520921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 142521398 and 142521407.

It is not a weakly prime, because it can be changed into another prime (142521473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71260716 + 71260717.

It is an arithmetic number, because the mean of its divisors is an integer number (71260717).

Almost surely, 2142521433 is an apocalyptic number.

It is an amenable number.

142521433 is a deficient number, since it is larger than the sum of its proper divisors (1).

142521433 is an equidigital number, since it uses as much as digits as its factorization.

142521433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2880, while the sum is 25.

The square root of 142521433 is about 11938.2340821413. The cubic root of 142521433 is about 522.3481490613.

Adding to 142521433 its reverse (334125241), we get a palindrome (476646674).

The spelling of 142521433 in words is "one hundred forty-two million, five hundred twenty-one thousand, four hundred thirty-three".