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14253411281 is a prime number
BaseRepresentation
bin11010100011001000…
…11100101111010001
31100210100022022111112
431101210130233101
5213142333130111
610314204023105
71013132665634
oct152144345721
940710268445
1014253411281
11605475194a
122919531a95
131461c77195
14992dddc1b
155864dce8b
hex35191cbd1

14253411281 has 2 divisors, whose sum is σ = 14253411282. Its totient is φ = 14253411280.

The previous prime is 14253411223. The next prime is 14253411323. The reversal of 14253411281 is 18211435241.

14253411281 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13874719681 + 378691600 = 117791^2 + 19460^2 .

It is a cyclic number.

It is not a de Polignac number, because 14253411281 - 218 = 14253149137 is a prime.

It is a super-3 number, since 3×142534112813 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (14253417281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7126705640 + 7126705641.

It is an arithmetic number, because the mean of its divisors is an integer number (7126705641).

Almost surely, 214253411281 is an apocalyptic number.

It is an amenable number.

14253411281 is a deficient number, since it is larger than the sum of its proper divisors (1).

14253411281 is an equidigital number, since it uses as much as digits as its factorization.

14253411281 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7680, while the sum is 32.

The spelling of 14253411281 in words is "fourteen billion, two hundred fifty-three million, four hundred eleven thousand, two hundred eighty-one".