Base | Representation |
---|---|
bin | 10100101111011110011… |
… | …101110001111111100001 |
3 | 12001021010020120201112001 |
4 | 110233132131301333201 |
5 | 141323122312230443 |
6 | 3010445423204001 |
7 | 204656624356105 |
oct | 24573635617741 |
9 | 5037106521461 |
10 | 1425366523873 |
11 | 4aa549275106 |
12 | 1b02b4446601 |
13 | a4547060706 |
14 | 4cdb9521905 |
15 | 271250d1d4d |
hex | 14bde771fe1 |
1425366523873 has 2 divisors, whose sum is σ = 1425366523874. Its totient is φ = 1425366523872.
The previous prime is 1425366523849. The next prime is 1425366523877. The reversal of 1425366523873 is 3783256635241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 965597091904 + 459769431969 = 982648^2 + 678063^2 .
It is an emirp because it is prime and its reverse (3783256635241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1425366523873 - 221 = 1425364426721 is a prime.
It is not a weakly prime, because it can be changed into another prime (1425366523877) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712683261936 + 712683261937.
It is an arithmetic number, because the mean of its divisors is an integer number (712683261937).
Almost surely, 21425366523873 is an apocalyptic number.
It is an amenable number.
1425366523873 is a deficient number, since it is larger than the sum of its proper divisors (1).
1425366523873 is an equidigital number, since it uses as much as digits as its factorization.
1425366523873 is an evil number, because the sum of its binary digits is even.
The product of its digits is 21772800, while the sum is 55.
The spelling of 1425366523873 in words is "one trillion, four hundred twenty-five billion, three hundred sixty-six million, five hundred twenty-three thousand, eight hundred seventy-three".
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