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1425366523877 is a prime number
BaseRepresentation
bin10100101111011110011…
…101110001111111100101
312001021010020120201112012
4110233132131301333211
5141323122312231002
63010445423204005
7204656624356112
oct24573635617745
95037106521465
101425366523877
114aa54927510a
121b02b4446605
13a454706070a
144cdb9521909
15271250d1d52
hex14bde771fe5

1425366523877 has 2 divisors, whose sum is σ = 1425366523878. Its totient is φ = 1425366523876.

The previous prime is 1425366523873. The next prime is 1425366523879. The reversal of 1425366523877 is 7783256635241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1386814772161 + 38551751716 = 1177631^2 + 196346^2 .

It is a cyclic number.

It is not a de Polignac number, because 1425366523877 - 22 = 1425366523873 is a prime.

It is a super-2 number, since 2×14253665238772 (a number of 25 digits) contains 22 as substring.

Together with 1425366523879, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1425366523873) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712683261938 + 712683261939.

It is an arithmetic number, because the mean of its divisors is an integer number (712683261939).

Almost surely, 21425366523877 is an apocalyptic number.

It is an amenable number.

1425366523877 is a deficient number, since it is larger than the sum of its proper divisors (1).

1425366523877 is an equidigital number, since it uses as much as digits as its factorization.

1425366523877 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 50803200, while the sum is 59.

The spelling of 1425366523877 in words is "one trillion, four hundred twenty-five billion, three hundred sixty-six million, five hundred twenty-three thousand, eight hundred seventy-seven".