Base | Representation |
---|---|
bin | 1100111101101100011001… |
… | …1101100110110011000111 |
3 | 1212110200010221022211121212 |
4 | 3033123012131212303013 |
5 | 3332014223432403431 |
6 | 50152113404002035 |
7 | 3000551115402161 |
oct | 317330635466307 |
9 | 55420127284555 |
10 | 14254031137991 |
11 | 45a6111a80537 |
12 | 172263a23031b |
13 | 7c51c3217498 |
14 | 373c823bb931 |
15 | 19aba7a8d72b |
hex | cf6c6766cc7 |
14254031137991 has 2 divisors, whose sum is σ = 14254031137992. Its totient is φ = 14254031137990.
The previous prime is 14254031137967. The next prime is 14254031138047. The reversal of 14254031137991 is 19973113045241.
It is a weak prime.
It is an emirp because it is prime and its reverse (19973113045241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14254031137991 - 214 = 14254031121607 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14254031137391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7127015568995 + 7127015568996.
It is an arithmetic number, because the mean of its divisors is an integer number (7127015568996).
Almost surely, 214254031137991 is an apocalyptic number.
14254031137991 is a deficient number, since it is larger than the sum of its proper divisors (1).
14254031137991 is an equidigital number, since it uses as much as digits as its factorization.
14254031137991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 816480, while the sum is 50.
The spelling of 14254031137991 in words is "fourteen trillion, two hundred fifty-four billion, thirty-one million, one hundred thirty-seven thousand, nine hundred ninety-one".
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