Base | Representation |
---|---|
bin | 1100111101110000110101… |
… | …1001000000010111100110 |
3 | 1212110210012212110220022001 |
4 | 3033130031121000113212 |
5 | 3332024143101124332 |
6 | 50152431433155514 |
7 | 3000622445132035 |
oct | 317341531002746 |
9 | 55423185426261 |
10 | 14255221114342 |
11 | 45a667276036a |
12 | 172291085bb9a |
13 | 7c535290c3c0 |
14 | 373d5645c71c |
15 | 19ac272990e7 |
hex | cf70d6405e6 |
14255221114342 has 64 divisors (see below), whose sum is σ = 23779705356288. Its totient is φ = 6367074336000.
The previous prime is 14255221114319. The next prime is 14255221114363. The reversal of 14255221114342 is 24341112255241.
14255221114342 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×142552211143422 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1287612667 + ... + 1287623737.
It is an arithmetic number, because the mean of its divisors is an integer number (371557896192).
Almost surely, 214255221114342 is an apocalyptic number.
14255221114342 is a deficient number, since it is larger than the sum of its proper divisors (9524484241946).
14255221114342 is a wasteful number, since it uses less digits than its factorization.
14255221114342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20765.
The product of its digits is 76800, while the sum is 37.
Adding to 14255221114342 its reverse (24341112255241), we get a palindrome (38596333369583).
The spelling of 14255221114342 in words is "fourteen trillion, two hundred fifty-five billion, two hundred twenty-one million, one hundred fourteen thousand, three hundred forty-two".
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