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142553001419 is a prime number
BaseRepresentation
bin1000010011000011010…
…0100010110111001011
3111121221202121210022022
42010300310202313023
54313422032021134
6145253221315055
713204411343063
oct2046064426713
9447852553268
10142553001419
11555024a8974
1223764865a8b
131059a78aa1a
146c847183a3
153a94e1b52e
hex2130d22dcb

142553001419 has 2 divisors, whose sum is σ = 142553001420. Its totient is φ = 142553001418.

The previous prime is 142553001329. The next prime is 142553001421. The reversal of 142553001419 is 914100355241.

It is a strong prime.

It is an emirp because it is prime and its reverse (914100355241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142553001419 - 236 = 73833524683 is a prime.

It is a super-2 number, since 2×1425530014192 (a number of 23 digits) contains 22 as substring.

Together with 142553001421, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (142553001319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71276500709 + 71276500710.

It is an arithmetic number, because the mean of its divisors is an integer number (71276500710).

Almost surely, 2142553001419 is an apocalyptic number.

142553001419 is a deficient number, since it is larger than the sum of its proper divisors (1).

142553001419 is an equidigital number, since it uses as much as digits as its factorization.

142553001419 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 35.

The spelling of 142553001419 in words is "one hundred forty-two billion, five hundred fifty-three million, one thousand, four hundred nineteen".