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1425613134017 is a prime number
BaseRepresentation
bin10100101111101101001…
…010100001100011000001
312001021202102121211001002
4110233231022201203001
5141324123430242032
63010530113021345
7204666010462112
oct24575512414301
95037672554032
101425613134017
114aa6654a2a46
121b0362b54855
13a4586187187
144d000198209
152713ba96862
hex14bed2a18c1

1425613134017 has 2 divisors, whose sum is σ = 1425613134018. Its totient is φ = 1425613134016.

The previous prime is 1425613133977. The next prime is 1425613134073. The reversal of 1425613134017 is 7104313165241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 843328152241 + 582284981776 = 918329^2 + 763076^2 .

It is an emirp because it is prime and its reverse (7104313165241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1425613134017 - 26 = 1425613133953 is a prime.

It is not a weakly prime, because it can be changed into another prime (1425613134317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712806567008 + 712806567009.

It is an arithmetic number, because the mean of its divisors is an integer number (712806567009).

Almost surely, 21425613134017 is an apocalyptic number.

It is an amenable number.

1425613134017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1425613134017 is an equidigital number, since it uses as much as digits as its factorization.

1425613134017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 38.

Adding to 1425613134017 its reverse (7104313165241), we get a palindrome (8529926299258).

The spelling of 1425613134017 in words is "one trillion, four hundred twenty-five billion, six hundred thirteen million, one hundred thirty-four thousand, seventeen".