Base | Representation |
---|---|
bin | 1100111101110100010011… |
… | …1110010110111100111011 |
3 | 1212110212121212012202220202 |
4 | 3033131010332112330323 |
5 | 3332033100313344201 |
6 | 50153104144512415 |
7 | 3000654530441552 |
oct | 317350476267473 |
9 | 55425555182822 |
10 | 14256153653051 |
11 | 45a7001097512 |
12 | 1722b3101b70b |
13 | 7c5470b8945b |
14 | 374004248d99 |
15 | 19ac7e0a1c6b |
hex | cf744f96f3b |
14256153653051 has 2 divisors, whose sum is σ = 14256153653052. Its totient is φ = 14256153653050.
The previous prime is 14256153653011. The next prime is 14256153653179. The reversal of 14256153653051 is 15035635165241.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14256153653051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14256153652987 and 14256153653005.
It is not a weakly prime, because it can be changed into another prime (14256153653011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7128076826525 + 7128076826526.
It is an arithmetic number, because the mean of its divisors is an integer number (7128076826526).
Almost surely, 214256153653051 is an apocalyptic number.
14256153653051 is a deficient number, since it is larger than the sum of its proper divisors (1).
14256153653051 is an equidigital number, since it uses as much as digits as its factorization.
14256153653051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620000, while the sum is 47.
The spelling of 14256153653051 in words is "fourteen trillion, two hundred fifty-six billion, one hundred fifty-three million, six hundred fifty-three thousand, fifty-one".
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