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14260166505353 is a prime number
BaseRepresentation
bin1100111110000011010000…
…1010001011001110001001
31212111020222112002210102002
43033200310022023032021
53332114310111132403
650155010254120345
73001156135224446
oct317406412131611
955436875083362
1014260166505353
1145a878025987a
121723870ab00b5
137c596035aa82
143742a51869cd
1519ae16515188
hexcf83428b389

14260166505353 has 2 divisors, whose sum is σ = 14260166505354. Its totient is φ = 14260166505352.

The previous prime is 14260166505307. The next prime is 14260166505359. The reversal of 14260166505353 is 35350566106241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12866626392064 + 1393540113289 = 3587008^2 + 1180483^2 .

It is a cyclic number.

It is not a de Polignac number, because 14260166505353 - 28 = 14260166505097 is a prime.

It is a super-3 number, since 3×142601665053533 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14260166505298 and 14260166505307.

It is not a weakly prime, because it can be changed into another prime (14260166505359) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7130083252676 + 7130083252677.

It is an arithmetic number, because the mean of its divisors is an integer number (7130083252677).

Almost surely, 214260166505353 is an apocalyptic number.

It is an amenable number.

14260166505353 is a deficient number, since it is larger than the sum of its proper divisors (1).

14260166505353 is an equidigital number, since it uses as much as digits as its factorization.

14260166505353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944000, while the sum is 47.

The spelling of 14260166505353 in words is "fourteen trillion, two hundred sixty billion, one hundred sixty-six million, five hundred five thousand, three hundred fifty-three".