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14260217053 is a prime number
BaseRepresentation
bin11010100011111100…
…11010010011011101
31100210211010002021011
431101332122103131
5213201103421203
610315005535221
71013244562555
oct152176322335
940724102234
1014260217053
116058580155
12291b874511
1314634bab74
14993c92165
15586dd476d
hex351f9a4dd

14260217053 has 2 divisors, whose sum is σ = 14260217054. Its totient is φ = 14260217052.

The previous prime is 14260217039. The next prime is 14260217057. The reversal of 14260217053 is 35071206241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8095140729 + 6165076324 = 89973^2 + 78518^2 .

It is a cyclic number.

It is not a de Polignac number, because 14260217053 - 25 = 14260217021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14260217057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7130108526 + 7130108527.

It is an arithmetic number, because the mean of its divisors is an integer number (7130108527).

Almost surely, 214260217053 is an apocalyptic number.

It is an amenable number.

14260217053 is a deficient number, since it is larger than the sum of its proper divisors (1).

14260217053 is an equidigital number, since it uses as much as digits as its factorization.

14260217053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 31.

The spelling of 14260217053 in words is "fourteen billion, two hundred sixty million, two hundred seventeen thousand, fifty-three".