Base | Representation |
---|---|
bin | 1000010011010100001… |
… | …1100101110001111111 |
3 | 111122010201022122200011 |
4 | 2010311003211301333 |
5 | 4314043224220044 |
6 | 145304240244051 |
7 | 13206233313451 |
oct | 2046503456177 |
9 | 448121278604 |
10 | 142624054399 |
11 | 55539619042 |
12 | 23784610627 |
13 | 105ac4078c8 |
14 | 6c8dd322d1 |
15 | 3a9b2a4134 |
hex | 21350e5c7f |
142624054399 has 2 divisors, whose sum is σ = 142624054400. Its totient is φ = 142624054398.
The previous prime is 142624054333. The next prime is 142624054411. The reversal of 142624054399 is 993450426241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142624054399 - 213 = 142624046207 is a prime.
It is a super-3 number, since 3×1426240543993 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142624054499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71312027199 + 71312027200.
It is an arithmetic number, because the mean of its divisors is an integer number (71312027200).
Almost surely, 2142624054399 is an apocalyptic number.
142624054399 is a deficient number, since it is larger than the sum of its proper divisors (1).
142624054399 is an equidigital number, since it uses as much as digits as its factorization.
142624054399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1866240, while the sum is 49.
The spelling of 142624054399 in words is "one hundred forty-two billion, six hundred twenty-four million, fifty-four thousand, three hundred ninety-nine".
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