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142645021481 is a prime number
BaseRepresentation
bin1000010011011001001…
…1100100101100101001
3111122012011202220002202
42010312103210230221
54314114111141411
6145310305505545
713206606451124
oct2046623445451
9448164686082
10142645021481
115554a439a06
122378b6422b5
13105b3869271
146c92a2d3bb
153a9d04683b
hex21364e4b29

142645021481 has 2 divisors, whose sum is σ = 142645021482. Its totient is φ = 142645021480.

The previous prime is 142645021429. The next prime is 142645021513. The reversal of 142645021481 is 184120546241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97141305625 + 45503715856 = 311675^2 + 213316^2 .

It is a cyclic number.

It is not a de Polignac number, because 142645021481 - 26 = 142645021417 is a prime.

It is a super-2 number, since 2×1426450214812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (142645021411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71322510740 + 71322510741.

It is an arithmetic number, because the mean of its divisors is an integer number (71322510741).

Almost surely, 2142645021481 is an apocalyptic number.

It is an amenable number.

142645021481 is a deficient number, since it is larger than the sum of its proper divisors (1).

142645021481 is an equidigital number, since it uses as much as digits as its factorization.

142645021481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 61440, while the sum is 38.

The spelling of 142645021481 in words is "one hundred forty-two billion, six hundred forty-five million, twenty-one thousand, four hundred eighty-one".