Base | Representation |
---|---|
bin | 11010100100101001… |
… | …01011100111001001 |
3 | 1100211020002200120121 |
4 | 31102110223213021 |
5 | 213204102230423 |
6 | 10315335023241 |
7 | 1013345316262 |
oct | 152224534711 |
9 | 40736080517 |
10 | 14266055113 |
11 | 60608a83a2 |
12 | 292180ab21 |
13 | 146478323b |
14 | 994971969 |
15 | 58768945d |
hex | 35252b9c9 |
14266055113 has 2 divisors, whose sum is σ = 14266055114. Its totient is φ = 14266055112.
The previous prime is 14266055099. The next prime is 14266055117. The reversal of 14266055113 is 31155066241.
14266055113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10626104889 + 3639950224 = 103083^2 + 60332^2 .
It is a cyclic number.
It is not a de Polignac number, because 14266055113 - 233 = 5676120521 is a prime.
It is not a weakly prime, because it can be changed into another prime (14266055117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7133027556 + 7133027557.
It is an arithmetic number, because the mean of its divisors is an integer number (7133027557).
Almost surely, 214266055113 is an apocalyptic number.
It is an amenable number.
14266055113 is a deficient number, since it is larger than the sum of its proper divisors (1).
14266055113 is an equidigital number, since it uses as much as digits as its factorization.
14266055113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600, while the sum is 34.
The spelling of 14266055113 in words is "fourteen billion, two hundred sixty-six million, fifty-five thousand, one hundred thirteen".
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