Base | Representation |
---|---|
bin | 10100110001001111000… |
… | …010101010101011010111 |
3 | 12001102222212112111221012 |
4 | 110301033002222223113 |
5 | 141341004320211211 |
6 | 3011401053042435 |
7 | 205054500245225 |
oct | 24611702525327 |
9 | 5042885474835 |
10 | 1427255241431 |
11 | 500328414608 |
12 | 1b0740a8641b |
13 | a4788443a76 |
14 | 4d1182cdb15 |
15 | 271d5d11d8b |
hex | 14c4f0aaad7 |
1427255241431 has 2 divisors, whose sum is σ = 1427255241432. Its totient is φ = 1427255241430.
The previous prime is 1427255241413. The next prime is 1427255241457. The reversal of 1427255241431 is 1341425527241.
Together with previous prime (1427255241413) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1427255241431 - 222 = 1427251047127 is a prime.
It is a super-2 number, since 2×14272552414312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1427255241131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 713627620715 + 713627620716.
It is an arithmetic number, because the mean of its divisors is an integer number (713627620716).
Almost surely, 21427255241431 is an apocalyptic number.
1427255241431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1427255241431 is an equidigital number, since it uses as much as digits as its factorization.
1427255241431 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 268800, while the sum is 41.
The spelling of 1427255241431 in words is "one trillion, four hundred twenty-seven billion, two hundred fifty-five million, two hundred forty-one thousand, four hundred thirty-one".
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