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1429990613281 is a prime number
BaseRepresentation
bin10100110011110010000…
…101010010000100100001
312001201001111121210200201
4110303302011102010201
5141412110044111111
63012532325345201
7205212333442246
oct24636205220441
95051044553621
101429990613281
1150150146a9aa
121b1184b68201
13a4b030635a9
144d2d76cd5cd
15272e60326c1
hex14cf2152121

1429990613281 has 2 divisors, whose sum is σ = 1429990613282. Its totient is φ = 1429990613280.

The previous prime is 1429990613257. The next prime is 1429990613297. The reversal of 1429990613281 is 1823160999241.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1426173350625 + 3817262656 = 1194225^2 + 61784^2 .

It is a cyclic number.

It is not a de Polignac number, because 1429990613281 - 217 = 1429990482209 is a prime.

It is a super-2 number, since 2×14299906132812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1429990613221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 714995306640 + 714995306641.

It is an arithmetic number, because the mean of its divisors is an integer number (714995306641).

Almost surely, 21429990613281 is an apocalyptic number.

It is an amenable number.

1429990613281 is a deficient number, since it is larger than the sum of its proper divisors (1).

1429990613281 is an equidigital number, since it uses as much as digits as its factorization.

1429990613281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1679616, while the sum is 55.

The spelling of 1429990613281 in words is "one trillion, four hundred twenty-nine billion, nine hundred ninety million, six hundred thirteen thousand, two hundred eighty-one".