Base | Representation |
---|---|
bin | 100000100000111100001011… |
… | …101011101001110010010100 |
3 | 200202022202220202210010012001 |
4 | 200200330023223221302110 |
5 | 122220412304310104134 |
6 | 1224045451351405044 |
7 | 42056330235245242 |
oct | 4040741353516224 |
9 | 622282822703161 |
10 | 143001132113044 |
11 | 41623492056237 |
12 | 140566b1983784 |
13 | 61a3c44955c7a |
14 | 27454126c1792 |
15 | 117ebc330b414 |
hex | 820f0bae9c94 |
143001132113044 has 48 divisors (see below), whose sum is σ = 255198108634560. Its totient is φ = 70094285465600.
The previous prime is 143001132113041. The next prime is 143001132113143. The reversal of 143001132113044 is 440311231100341.
It is a super-2 number, since 2×1430011321130442 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143001132113041) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 176044194 + ... + 176854630.
It is an arithmetic number, because the mean of its divisors is an integer number (5316627263220).
Almost surely, 2143001132113044 is an apocalyptic number.
It is an amenable number.
143001132113044 is a deficient number, since it is larger than the sum of its proper divisors (112196976521516).
143001132113044 is a wasteful number, since it uses less digits than its factorization.
143001132113044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 812568 (or 812566 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 143001132113044 its reverse (440311231100341), we get a palindrome (583312363213385).
The spelling of 143001132113044 in words is "one hundred forty-three trillion, one billion, one hundred thirty-two million, one hundred thirteen thousand, forty-four".
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