Base | Representation |
---|---|
bin | 1101000000011001001110… |
… | …1100101101100101101001 |
3 | 1212122002220010212111121111 |
4 | 3100012103230231211221 |
5 | 3333244232032201301 |
6 | 50225305114110321 |
7 | 3004112561151601 |
oct | 320062354554551 |
9 | 55562803774544 |
10 | 14300424100201 |
11 | 4613859658718 |
12 | 172b62711b3a1 |
13 | 7c96a78b1905 |
14 | 376203a49c01 |
15 | 19bec0931551 |
hex | d0193b2d969 |
14300424100201 has 2 divisors, whose sum is σ = 14300424100202. Its totient is φ = 14300424100200.
The previous prime is 14300424100141. The next prime is 14300424100219. The reversal of 14300424100201 is 10200142400341.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9789239258176 + 4511184842025 = 3128776^2 + 2123955^2 .
It is a cyclic number.
It is not a de Polignac number, because 14300424100201 - 27 = 14300424100073 is a prime.
It is not a weakly prime, because it can be changed into another prime (14300424110201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7150212050100 + 7150212050101.
It is an arithmetic number, because the mean of its divisors is an integer number (7150212050101).
Almost surely, 214300424100201 is an apocalyptic number.
It is an amenable number.
14300424100201 is a deficient number, since it is larger than the sum of its proper divisors (1).
14300424100201 is an equidigital number, since it uses as much as digits as its factorization.
14300424100201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 14300424100201 its reverse (10200142400341), we get a palindrome (24500566500542).
The spelling of 14300424100201 in words is "fourteen trillion, three hundred billion, four hundred twenty-four million, one hundred thousand, two hundred one".
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