Base | Representation |
---|---|
bin | 1101000000011001010000… |
… | …1111110100001000011100 |
3 | 1212122002220210012000011111 |
4 | 3100012110033310020130 |
5 | 3333244241411131134 |
6 | 50225310043231404 |
7 | 3004113032315251 |
oct | 320062417641034 |
9 | 55562823160144 |
10 | 14300433302044 |
11 | 461386387314a |
12 | 172b62a218564 |
13 | 7c96a97840a6 |
14 | 376204d63428 |
15 | 19bec164cc64 |
hex | d01943f421c |
14300433302044 has 24 divisors (see below), whose sum is σ = 25038079743600. Its totient is φ = 7146696888576.
The previous prime is 14300433302011. The next prime is 14300433302047. The reversal of 14300433302044 is 44020333400341.
It is a super-2 number, since 2×143004333020442 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14300433301997 and 14300433302015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14300433302047) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 93600564 + ... + 93753220.
It is an arithmetic number, because the mean of its divisors is an integer number (1043253322650).
Almost surely, 214300433302044 is an apocalyptic number.
It is an amenable number.
14300433302044 is a deficient number, since it is larger than the sum of its proper divisors (10737646441556).
14300433302044 is a wasteful number, since it uses less digits than its factorization.
14300433302044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 164037 (or 164035 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 14300433302044 its reverse (44020333400341), we get a palindrome (58320766702385).
The spelling of 14300433302044 in words is "fourteen trillion, three hundred billion, four hundred thirty-three million, three hundred two thousand, forty-four".
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