Base | Representation |
---|---|
bin | 1101000000011001111011… |
… | …1010110111111100100111 |
3 | 1212122010101021010012021120 |
4 | 3100012132322313330213 |
5 | 3333300123231041043 |
6 | 50225335521145023 |
7 | 3004120335310101 |
oct | 320063672677447 |
9 | 55563337105246 |
10 | 14300612362023 |
11 | 46139459535a9 |
12 | 172b67a18b173 |
13 | 7c97078b9140 |
14 | 376220a54571 |
15 | 19bed221c983 |
hex | d019eeb7f27 |
14300612362023 has 32 divisors (see below), whose sum is σ = 20575277184000. Its totient is φ = 8782787460096.
The previous prime is 14300612362021. The next prime is 14300612362039. The reversal of 14300612362023 is 32026321600341.
It is a happy number.
It is not a de Polignac number, because 14300612362023 - 21 = 14300612362021 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14300612362021) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 71829111 + ... + 72027927.
It is an arithmetic number, because the mean of its divisors is an integer number (642977412000).
Almost surely, 214300612362023 is an apocalyptic number.
14300612362023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
14300612362023 is a deficient number, since it is larger than the sum of its proper divisors (6274664821977).
14300612362023 is a wasteful number, since it uses less digits than its factorization.
14300612362023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 202511.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 14300612362023 its reverse (32026321600341), we get a palindrome (46326933962364).
The spelling of 14300612362023 in words is "fourteen trillion, three hundred billion, six hundred twelve million, three hundred sixty-two thousand, twenty-three".
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