Base | Representation |
---|---|
bin | 10100110011111000101… |
… | …011111100010110110101 |
3 | 12001201100020002220221022 |
4 | 110303320223330112311 |
5 | 141412321430130003 |
6 | 3012551324230525 |
7 | 205215150266354 |
oct | 24637053742665 |
9 | 5051306086838 |
10 | 1430101411253 |
11 | 501558a67079 |
12 | 1b11b609b445 |
13 | a4b1ccb7c18 |
14 | 4d3082d199b |
15 | 27300b1b738 |
hex | 14cf8afc5b5 |
1430101411253 has 2 divisors, whose sum is σ = 1430101411254. Its totient is φ = 1430101411252.
The previous prime is 1430101411231. The next prime is 1430101411283. The reversal of 1430101411253 is 3521141010341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 889820549809 + 540280861444 = 943303^2 + 735038^2 .
It is a cyclic number.
It is not a de Polignac number, because 1430101411253 - 210 = 1430101410229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1430101411283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715050705626 + 715050705627.
It is an arithmetic number, because the mean of its divisors is an integer number (715050705627).
Almost surely, 21430101411253 is an apocalyptic number.
It is an amenable number.
1430101411253 is a deficient number, since it is larger than the sum of its proper divisors (1).
1430101411253 is an equidigital number, since it uses as much as digits as its factorization.
1430101411253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 1430101411253 its reverse (3521141010341), we get a palindrome (4951242421594).
The spelling of 1430101411253 in words is "one trillion, four hundred thirty billion, one hundred one million, four hundred eleven thousand, two hundred fifty-three".
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