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14301014213 is a prime number
BaseRepresentation
bin11010101000110100…
…00010100011000101
31100220122212210110002
431110122002203011
5213242024423323
610323024211045
71014251420663
oct152432024305
940818783402
1014301014213
116079605712
122931469a85
13146baa34b5
14999471c33
1558a792828
hex3546828c5

14301014213 has 2 divisors, whose sum is σ = 14301014214. Its totient is φ = 14301014212.

The previous prime is 14301014201. The next prime is 14301014219. The reversal of 14301014213 is 31241010341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13988502529 + 312511684 = 118273^2 + 17678^2 .

It is an emirp because it is prime and its reverse (31241010341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14301014213 - 28 = 14301013957 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14301014219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7150507106 + 7150507107.

It is an arithmetic number, because the mean of its divisors is an integer number (7150507107).

Almost surely, 214301014213 is an apocalyptic number.

It is an amenable number.

14301014213 is a deficient number, since it is larger than the sum of its proper divisors (1).

14301014213 is an equidigital number, since it uses as much as digits as its factorization.

14301014213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 14301014213 its reverse (31241010341), we get a palindrome (45542024554).

The spelling of 14301014213 in words is "fourteen billion, three hundred one million, fourteen thousand, two hundred thirteen".