Base | Representation |
---|---|
bin | 1000010100110000110… |
… | …0101001101000000011 |
3 | 111200010202212211221021 |
4 | 2011030030221220003 |
5 | 4320342122233121 |
6 | 145410550010311 |
7 | 13221656352553 |
oct | 2051414515003 |
9 | 450122784837 |
10 | 143012305411 |
11 | 55718799848 |
12 | 23872646997 |
13 | 10641994531 |
14 | 6cc9719163 |
15 | 3ac03e6641 |
hex | 214c329a03 |
143012305411 has 2 divisors, whose sum is σ = 143012305412. Its totient is φ = 143012305410.
The previous prime is 143012305357. The next prime is 143012305439. The reversal of 143012305411 is 114503210341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143012305411 - 29 = 143012304899 is a prime.
It is not a weakly prime, because it can be changed into another prime (143012305481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71506152705 + 71506152706.
It is an arithmetic number, because the mean of its divisors is an integer number (71506152706).
Almost surely, 2143012305411 is an apocalyptic number.
143012305411 is a deficient number, since it is larger than the sum of its proper divisors (1).
143012305411 is an equidigital number, since it uses as much as digits as its factorization.
143012305411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 143012305411 its reverse (114503210341), we get a palindrome (257515515752).
The spelling of 143012305411 in words is "one hundred forty-three billion, twelve million, three hundred five thousand, four hundred eleven".
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