Base | Representation |
---|---|
bin | 10100110011111100000… |
… | …110100110000110011111 |
3 | 12001201111012221222222012 |
4 | 110303330012212012133 |
5 | 141412431113322011 |
6 | 3013001132541435 |
7 | 205216444424342 |
oct | 24637406460637 |
9 | 5051435858865 |
10 | 1430158729631 |
11 | 501588356235 |
12 | 1b121132187b |
13 | a4b2bb36418 |
14 | 4d311b72459 |
15 | 27305b8ea8b |
hex | 14cfc1a619f |
1430158729631 has 2 divisors, whose sum is σ = 1430158729632. Its totient is φ = 1430158729630.
The previous prime is 1430158729609. The next prime is 1430158729739. The reversal of 1430158729631 is 1369278510341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1430158729631 - 218 = 1430158467487 is a prime.
It is a super-2 number, since 2×14301587296312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1430158729631.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1430158726631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715079364815 + 715079364816.
It is an arithmetic number, because the mean of its divisors is an integer number (715079364816).
It is a 2-persistent number, because it is pandigital, and so is 2⋅1430158729631 = 2860317459262, but 3⋅1430158729631 = 4290476188893 is not.
Almost surely, 21430158729631 is an apocalyptic number.
1430158729631 is a deficient number, since it is larger than the sum of its proper divisors (1).
1430158729631 is an equidigital number, since it uses as much as digits as its factorization.
1430158729631 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1088640, while the sum is 50.
The spelling of 1430158729631 in words is "one trillion, four hundred thirty billion, one hundred fifty-eight million, seven hundred twenty-nine thousand, six hundred thirty-one".
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