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143020130044 = 22115119634979
BaseRepresentation
bin1000010100110010101…
…0011111111011111100
3111200011022121101022111
42011030222133323330
54320401123130134
6145411425423404
713222113022111
oct2051452377374
9450138541274
10143020130044
1155722153590
122387519ab64
13106434a3bac
146cca794908
153ac0e3ec64
hex214ca9fefc

143020130044 has 24 divisors (see below), whose sum is σ = 273092198400. Its totient is φ = 64996348080.

The previous prime is 143020130041. The next prime is 143020130053. The reversal of 143020130044 is 440031020341.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a junction number, because it is equal to n+sod(n) for n = 143020129997 and 143020130024.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143020130041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 92254 + ... + 542725.

It is an arithmetic number, because the mean of its divisors is an integer number (11378841600).

Almost surely, 2143020130044 is an apocalyptic number.

It is an amenable number.

143020130044 is a deficient number, since it is larger than the sum of its proper divisors (130072068356).

143020130044 is a wasteful number, since it uses less digits than its factorization.

143020130044 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 640113 (or 640111 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 143020130044 its reverse (440031020341), we get a palindrome (583051150385).

The spelling of 143020130044 in words is "one hundred forty-three billion, twenty million, one hundred thirty thousand, forty-four".

Divisors: 1 2 4 11 22 44 5119 10238 20476 56309 112618 225236 634979 1269958 2539916 6984769 13969538 27939076 3250457501 6500915002 13001830004 35755032511 71510065022 143020130044