Base | Representation |
---|---|
bin | 1000010100110010101… |
… | …0011111111011111100 |
3 | 111200011022121101022111 |
4 | 2011030222133323330 |
5 | 4320401123130134 |
6 | 145411425423404 |
7 | 13222113022111 |
oct | 2051452377374 |
9 | 450138541274 |
10 | 143020130044 |
11 | 55722153590 |
12 | 2387519ab64 |
13 | 106434a3bac |
14 | 6cca794908 |
15 | 3ac0e3ec64 |
hex | 214ca9fefc |
143020130044 has 24 divisors (see below), whose sum is σ = 273092198400. Its totient is φ = 64996348080.
The previous prime is 143020130041. The next prime is 143020130053. The reversal of 143020130044 is 440031020341.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is a junction number, because it is equal to n+sod(n) for n = 143020129997 and 143020130024.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143020130041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 92254 + ... + 542725.
It is an arithmetic number, because the mean of its divisors is an integer number (11378841600).
Almost surely, 2143020130044 is an apocalyptic number.
It is an amenable number.
143020130044 is a deficient number, since it is larger than the sum of its proper divisors (130072068356).
143020130044 is a wasteful number, since it uses less digits than its factorization.
143020130044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 640113 (or 640111 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 143020130044 its reverse (440031020341), we get a palindrome (583051150385).
The spelling of 143020130044 in words is "one hundred forty-three billion, twenty million, one hundred thirty thousand, forty-four".
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