14302134107 has 2 divisors, whose sum is σ = 14302134108. Its totient is φ = 14302134106.

The previous prime is 14302134071. The next prime is 14302134109. The reversal of 14302134107 is 70143120341.

Together with previous prime (14302134071) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14302134107 - 2²⁰ = 14301085531 is a prime.

It is a super-2 number, since 2×14302134107² (a number of 21 digits) contains 22 as substring.

Together with 14302134109, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14302134109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7151067053 + 7151067054.

It is an arithmetic number, because the mean of its divisors is an integer number (7151067054).

Almost surely, 2^14302134107 is an apocalyptic number.

14302134107 is a deficient number, since it is larger than the sum of its proper divisors (1).

14302134107 is an equidigital number, since it uses as much as digits as its factorization.

14302134107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 26.

Adding to 14302134107 its reverse (70143120341), we get a palindrome (84445254448).

The spelling of 14302134107 in words is "fourteen billion, three hundred two million, one hundred thirty-four thousand, one hundred seven".