Base | Representation |
---|---|
bin | 100000100001010111001011… |
… | …000001001100001100100011 |
3 | 200202102112201102120110200120 |
4 | 200201113023001030030203 |
5 | 122221401132133323133 |
6 | 1224111043143251323 |
7 | 42061404340310625 |
oct | 4041271301141443 |
9 | 622375642513616 |
10 | 143030112011043 |
11 | 41634803496564 |
12 | 1406023b149b43 |
13 | 61a68b28931ca |
14 | 27469a1468c15 |
15 | 118081c5d2ab3 |
hex | 8215cb04c323 |
143030112011043 has 64 divisors (see below), whose sum is σ = 202681227248640. Its totient is φ = 89588282370048.
The previous prime is 143030112011041. The next prime is 143030112011107. The reversal of 143030112011043 is 340110211030341.
It is a happy number.
It is not a de Polignac number, because 143030112011043 - 21 = 143030112011041 is a prime.
It is a super-2 number, since 2×1430301120110432 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (143030112011041) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 141319930 + ... + 142328432.
It is an arithmetic number, because the mean of its divisors is an integer number (3166894175760).
Almost surely, 2143030112011043 is an apocalyptic number.
143030112011043 is a deficient number, since it is larger than the sum of its proper divisors (59651115237597).
143030112011043 is a wasteful number, since it uses less digits than its factorization.
143030112011043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1008908.
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 143030112011043 its reverse (340110211030341), we get a palindrome (483140323041384).
The spelling of 143030112011043 in words is "one hundred forty-three trillion, thirty billion, one hundred twelve million, eleven thousand, forty-three".
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