Base | Representation |
---|---|
bin | 10100110100000100110… |
… | …101100010001110000111 |
3 | 12001201212102200010012011 |
4 | 110310010311202032013 |
5 | 141413231121032411 |
6 | 3013023445235051 |
7 | 205223204022052 |
oct | 24640465421607 |
9 | 5051772603164 |
10 | 1430305252231 |
11 | 501653032899 |
12 | 1b1252402a87 |
13 | a4b532b859b |
14 | 4d3273d3a99 |
15 | 27313983c21 |
hex | 14d04d62387 |
1430305252231 has 2 divisors, whose sum is σ = 1430305252232. Its totient is φ = 1430305252230.
The previous prime is 1430305252223. The next prime is 1430305252247. The reversal of 1430305252231 is 1322525030341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1430305252231 - 23 = 1430305252223 is a prime.
It is a super-2 number, since 2×14303052522312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1430305252193 and 1430305252202.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1430305252531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715152626115 + 715152626116.
It is an arithmetic number, because the mean of its divisors is an integer number (715152626116).
Almost surely, 21430305252231 is an apocalyptic number.
1430305252231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1430305252231 is an equidigital number, since it uses as much as digits as its factorization.
1430305252231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 31.
The spelling of 1430305252231 in words is "one trillion, four hundred thirty billion, three hundred five million, two hundred fifty-two thousand, two hundred thirty-one".
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