143031343240 has 32 divisors (see below), whose sum is σ = 321883128000. Its totient is φ = 57201407424.

The previous prime is 143031343229. The next prime is 143031343267. The reversal of 143031343240 is 42343130341.

It is a super-3 number, since 3×143031343240³ (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143031343199 and 143031343208.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 138060 + ... + 552379.

It is an arithmetic number, because the mean of its divisors is an integer number (10058847750).

Almost surely, 2^143031343240 is an apocalyptic number.

143031343240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

143031343240 is an abundant number, since it is smaller than the sum of its proper divisors (178851784760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143031343240 is a wasteful number, since it uses less digits than its factorization.

143031343240 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 695629 (or 695625 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 143031343240 its reverse (42343130341), we get a palindrome (185374473581).

The spelling of 143031343240 in words is "one hundred forty-three billion, thirty-one million, three hundred forty-three thousand, two hundred forty".