143031413131 has 2 divisors, whose sum is σ = 143031413132. Its totient is φ = 143031413130.

The previous prime is 143031413099. The next prime is 143031413141. The reversal of 143031413131 is 131314130341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 143031413131 - 2⁵ = 143031413099 is a prime.

It is a super-2 number, since 2×143031413131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143031413096 and 143031413105.

It is not a weakly prime, because it can be changed into another prime (143031413141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71515706565 + 71515706566.

It is an arithmetic number, because the mean of its divisors is an integer number (71515706566).

Almost surely, 2^143031413131 is an apocalyptic number.

143031413131 is a deficient number, since it is larger than the sum of its proper divisors (1).

143031413131 is an equidigital number, since it uses as much as digits as its factorization.

143031413131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 143031413131 its reverse (131314130341), we get a palindrome (274345543472).

The spelling of 143031413131 in words is "one hundred forty-three billion, thirty-one million, four hundred thirteen thousand, one hundred thirty-one".