Base | Representation |
---|---|
bin | 1101000000100011100100… |
… | …1110001111111110001111 |
3 | 1212122101001200100100200001 |
4 | 3100020321032033332033 |
5 | 3333320423442214211 |
6 | 50230444435345131 |
7 | 3004241441430511 |
oct | 320107116177617 |
9 | 55571050310601 |
10 | 14303201132431 |
11 | 4614a54179082 |
12 | 17300811521a7 |
13 | 7c9a2b029953 |
14 | 3763c87b1bb1 |
15 | 19c0d4630ac1 |
hex | d023938ff8f |
14303201132431 has 2 divisors, whose sum is σ = 14303201132432. Its totient is φ = 14303201132430.
The previous prime is 14303201132393. The next prime is 14303201132443. The reversal of 14303201132431 is 13423110230341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14303201132431 - 223 = 14303192743823 is a prime.
It is a super-2 number, since 2×143032011324312 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14303201132431.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14303201136431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7151600566215 + 7151600566216.
It is an arithmetic number, because the mean of its divisors is an integer number (7151600566216).
Almost surely, 214303201132431 is an apocalyptic number.
14303201132431 is a deficient number, since it is larger than the sum of its proper divisors (1).
14303201132431 is an equidigital number, since it uses as much as digits as its factorization.
14303201132431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 14303201132431 its reverse (13423110230341), we get a palindrome (27726311362772).
The spelling of 14303201132431 in words is "fourteen trillion, three hundred three billion, two hundred one million, one hundred thirty-two thousand, four hundred thirty-one".
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